A rectangular area of sides 9 and 6 units is to be covered by square tiles of sides 1, 2 and 5 units. The minimum number of tiles needed for this is
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Answered by
1
Answer:
rectangek area =9X6=54sq units
area of first tile=1X1=1
sq units
second tile =2X2 =4 sq units
third tile =5X5 = 25 sq units
required ni if tiles
second tile 1
third tiles 50
Answered by
9
Answer:
12
Step-by-step explanation:
Total area = 9×6= 54 sq units
1×1 = 1 sq unit
2×2= 4 sq units
5×5= 25 sq units
If we arrange the tiles as one 5 units tiles, six 2 unit tiles and five 1 unit tile i.e.
area = 25+6×4+1×5 = 54 sq units
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