Math, asked by vishalydv8299, 4 months ago

A rectangular area of sides 9 and 6 units is to be covered by square tiles of sides 1, 2 and 5 units. The minimum number of tiles needed for this is

Answers

Answered by lahari60
1

Answer:

rectangek area =9X6=54sq units

area of first tile=1X1=1

sq units

second tile =2X2 =4 sq units

third tile =5X5 = 25 sq units

required ni if tiles

second tile 1

third tiles 50

Answered by rajita18
9

Answer:

12

Step-by-step explanation:

Total area = 9×6= 54 sq units

1×1 = 1 sq unit

2×2= 4 sq units

5×5= 25 sq units

If we arrange the tiles as one 5 units tiles, six 2 unit tiles and five 1 unit tile i.e.

area = 25+6×4+1×5 = 54 sq units

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