Question

A rectangular bathroom floor is covered with square tiles that are 1 ½ feet by 1 ½ feet. The length of the bathroom floor is 10 ½ feet and the width is 6 ½ feet. How many tiles does it take to cover the width of the floor?

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Part 1) It takes 7 tiles to cover the length of the floor

part 2) It takes 4 1/3 tiles to cover the width of the floor

Step-by-step explanation:

step 1

we know that

To find out how many tiles are needed to cover the length of the floor, divide the length of the floor by the length of one square tile

$10\frac{1}{2}:1\frac{1}{2}10$

Convert mixed number to an improper fraction

$10\frac{1}{2}\ ft=10+\frac{1}{2}=\frac{10*2+1}{2}=\frac{21}{2}\ ft10$

$1\frac{1}{2}\ ft=1+\frac{1}{2}=\frac{1*2+1}{2}=\frac{3}{2}\ ft1$

substitute

$\frac{21}{2}:\frac{3}{2}=\frac{21}{3}=7\ tiles$

step 2

To find out how many tiles are needed to cover the width of the floor, divide the width of the floor by the length of one square tile

$6\frac{1}{2}:1\frac{1}{2}6$

Convert mixed number to an improper fraction

$6\frac{1}{2}\ ft=6+\frac{1}{2}=\frac{6*2+1}{2}=\frac{13}{2}\ ft6$

$1\frac{1}{2}\ ft=1+\frac{1}{2}=\frac{1*2+1}{2}=\frac{3}{2}\ ft1$

$\frac{13}{2}:\frac{3}{2}=\frac{13}{3}\ tiles/[tex] </p><p></p><p></p><p>Convert to mixed number</p><p></p><p>[tex]\frac{13}{3}\ tiles=\frac{12}{3}+\frac{1}{3}=4\frac{1}{3}\ tiles$

313

tiles= 12 + 31

=4 31 tiles