Chemistry, asked by adhaka502, 4 months ago

A rectangular beam 300 mm deep is simply
supported
over a span of 4m . what
Uniformly distributed load per metre the
may carry, it the bending
stress is not to
exceed
120 N/mm² ? Take I =8×10⁶mm ( answer = 3200N/m )

Answers

Answered by jyotibamba
6

Answer:

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Answered by parvatimatas4
2

Given data:  = 130 N/mm2 I = 8.5 × 106 mm4 y = d/2 = 300/2 = 150mm L = 5m = 5000mm Let UDL = W N/mMaximum bending moment for a simply supported beam with UDL on its entire span is given by = WL2/8 i.e; M = WL2/8 ...i Now from bending equation M/I = σ/ymax M = Ã.I/ymax = [130 × 8.5 × 106]/ 150 = 7366666.67 Nmm ...iiSubstituting this value in equation i; we get 7366666.67 = W50002/8 W = 2.357 N/mm = 2357.3 N/m

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