A rectangular block having a weight of 500N has the following dimensions 100cm x 50cm x 10cm. If the block is kept on a horizontal table,
(a) Calculate the maximum pressure that it can exert on the table.
(b) Calculate the minimum pressure that it can exert on the table.
Answers
Answer:
Explanation:
PRESSURE=FORCE/AREA
when area is smallest pressure is largest
as force is constant we will try to find smallest are which will have max pressure and largest area which will have minimum pressure
a) We have to calculate minimum area as there is max pressure.
area of the surfaces will be
100x50
10x50
10x100
10 x 50 is the smallest
=500cm^2
but we have to convert to SI units to solve as Newton is also in Si units
500cm^2=500/10000 m^2= 5 x 100/10000 m^2
=5 x 10^-2 m^2
Force=500N
Pressure= 500/5 x 10^-2=500 x 10^2/5=100 x 100=10000 Pa= Max pressure
b) We have to calculate maximum area as there is minimum pressure.
area of the surfaces will be
100x50
10x50
10x100
100 x 50 is the largest
=5000cm^2
but we have to convert to SI units to solve as Newton is also in Si units
5000cm^2=5000/10000 m^2= 5 x 1000/10000 m^2
=5 x 10^-1 m^2
Force=500N
Pressure= 500/5 x 10^-1=500 x 10^1/5=100 x 10=1000 Pa= Minimum pressure
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Answer:
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