Question

A rectangular block is moved 5m horizontally with a force of 150N. Find the work done on the block.
pls show the solution:
thank you​

Answer 1

$work \: done \: = \: force \times displacement$

$force = 150 \: newton$

$displacement = 5m$

$work \: done = 150 \times 5$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 750 \: joules$

Hope it helps you

Answer 2

Explanation:

Given,

Force ( F ) = 150 N

Displacement ( s ) = 5m

To find : Work done ( W ) = ?

Formula : -

W = F × s

= 150 × 5

W = 750 N/m

Therefore, the work done on the block is

750 N/m.