Physics, asked by jenny1379, 7 months ago

A rectangular block measures
4m×3m×2m . it weighs 600 N and rest with one face on level ground . Draw a diagram to show the position of the block when the pressure under it is :
a. as high as possible
b.as low as possible
calculate the pressure in each case .
( area of rectangle = length × width )​

Answers

Answered by tripathiakshita48
4

Answer:

The minimum position is 600 N / 10 m2 = 60 N/m2.

The pressure under the block when it is in its maximum position = 50 N/m2.

Explanation:

From the above question,

They have given :

A rectangular block measures 4m×3m×2m . it weighs 600 N and rest with one face on level ground . Draw a diagram to show the position of the block when the pressure under it is,

(a) As High As Possible :

  • The diagram below shows the position of the block when the pressure under it is as high as possible. The rectangular block is placed on a level ground with two of its faces (3m × 2m and 4m × 2m) facing the ground. The other two faces (4m × 3m and 3m × 2m) are facing up. The pressure under the block is as high as possible.
  • In this case, the area of the two faces facing the ground is 12 m2 (3m × 4m + 2m × 4m). Therefore, the pressure under the block when it is in its maximum position is 600 N / 12 m2 = 50 N/m2.

(b) As Low As Possible :

  • The diagram below shows the position of the block when the pressure under it is as low as possible. The rectangular block is placed on a level ground with two of its faces (4m × 3m and 3m × 2m) facing the ground. The other two faces (4m × 2m and 3m × 2m) are facing up. The pressure under the block is as low as possible.
  • Therefore, the pressure under the block when it is in its minimum position is 600 N / 10 m2 = 60 N/m2.

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