Physics, asked by prabha86, 1 year ago

A rectangular block of dimension 6m×4m×2m and of density 1.5gm/cc is lying on horizontal ground with the face of largest area in contact with the ground.The work done in arranging it with its smallest area in contact with the ground is​

Answers

Answered by TripathyUsha
14

Answer:

Explanation:

Volume of block=6*2*4=48m^3

AND MASS = v x D = 72 g

also work done on block by gravity when we arrange in

smallest area=MGH =10*72*2*1000 .=.1440KJ

Answered by parveennidatasneem
4

Answer:

1440J

Explanation:

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