Question

A rectangular block of mass 400 g is placed on top of a table. The area of contact is 80 cm2 , find the pressure exerted by the block on the table.

Answer 1

Answer:

Correct option is

B

(a) P=2450Nm

−2

(b) P=612.5Nm

−2

Mass of the wooden block, m=5kg

Thrust due to wooden block,

Mg=5kg×9.8ms

−2

=49N

(a) Surface area of 20cm×10cm surface,

A=(20×10)cm

2

=(0.2×0.1)m

2

=0.02m

2

P=

A

mg

P=

0.02m

2

49N

=

0.02

49

Nm

−2

or Pressure, P=2450Nm

−2

.

(b) Surface area of 40cm×20cm surface,

A=(40×20)cm

2

=(0.4×0.2)m

2

=0.08m

2

P=

0.08m

2

49N

=

0.08

49

Nm

−2

or Pressure, P=612.5Nm

−2

.