Question

A rectangular block of mass 6 kg is to be held against a rough vertical wall by applying a
force perpendicular to the wall. Find the minimum force to be applied the coefficient of
friction is 0.4
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Answer 1

The minimum force applied is 140 N.

Explanation:

F(g) = Force due to gravity

F(N) = Applied force ( Normal force)

F(r) = Frictional force

F(f) = μ F(N)

μ = 0.4

F(f) > F(g)   [ To cancel the downward force]

For minimum

F(f) = F(g) = 0.42 x F(n)

M(g) = 0.42 x F(N)

6 x 9.8 = 0.42  x F(N)

F(N) = 140 N

Hence the minimum force applied is 140 N.

Also learn more

A minimum force F is applied to a block of mass 102 kg to  prevent it from sliding on a plane with an inclination angle  30° with the horizontal. If the coefficients of static and  kinetic friction between the block and the plane are 0.4  and 0.3 respectively, then the force F is:?

https://brainly.in/question/12494136

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