a rectangular block of mass 6 kg is to be held against a rough vertical wall bt applying a force perpendicular to the wall what is the minimum for ce to be applied if the coefficient of Friction is 0.42
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The minimum force applied is 140 N.
Explanation:
F(g) = Force due to gravity
F(N) = Applied force ( Normal force)
F(r) = Frictional force
F(f) = μ F(N)
μ = 0.4
F(f) > F(g) [ To cancel the downward force]
For minimum
F(f) = F(g) = 0.42 x F(n)
M(g) = 0.42 x F(N)
6 x 9.8 = 0.42 x F(N)
F(N) = 140 N
Hence the minimum force applied is 140 N.
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