Question

A rectangular block of side 20cm x 10cm applies a force of 240N. Calculate the pressure exerted by the block on the ground

Answer 1

Answer:

4.8

Explanation:

........Mmmmmmmmmmmmmm

Answer 2

Given :-

Length of the rectangular block = 20 cm

Breadth of the rectangular block = 10 cm

Force applied = 240 N

To Find :-

The pressure exerted by the block on the ground.

Solution :-

We know that,

• p = Pressure
• f = Force
• a = Area
• l = Length
• b = Breadth

Using the formula,

$\underline{\boxed{\sf Area \ of \ the \ rectangle=Length \times Breadth}}$

Given that,

Length (l) = 20 cm

Breadth (b) = 10 cm

Substituting their values,

a = 20 × 10

a = 200 cm²

Using the formula,

$\underline{\boxed{\sf Pressure=\dfrac{Force}{Area} }}$

Given that,

Area = 200 cm² = 0.02 m²

Force (f) = 240 N

Substituting their values,

p = 240/0.02

p = 12000 Pa

Therefore, the pressure exerted by the block on the ground is 12000 Pa.