A rectangular block of wood floats in water with two-third of its volume immersed.When placed in another liquid ,it floats with half of its volume immersed. calculate the relative density of the liquid.
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Answer:
The first liquid’s density is 3/4 of the second.
Explanation:
The calculation of relative density of the liquids is below :
Weight of the block - mg
total volume - V1
Volume of liquid displaced by the floating object- V2
Densities of the two liquids - d1, d2
For floating as per Archimedes law:
mg-V2=0
V2= mg
Hence V1*d1*2/3 = mg; and V1*d2*1/2 =mg
equating both d1*2/3=d2*1/2
simplifying it we get d1/d2 = 1/2*3/2 = 3/4
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