Question

A rectangular block that exerts a force of 50 N on the ground, determine the least pressure exerted by the block. Rectangular block length is 15 cm, breadth is 20 cm and height is 6 cm

Answer 1

Heya user !!!

Here's the answer you are looking for

Pressure is inversely proportional to area.

So if area is least, pressure is maximum and if area is max pressure is least.

So, in your question, for least pressure, area of block must be max.

It's breadth (b) = 15cm

and length (l) = 20cm

and height (h) = 6cm

So, max area = l × b = 20 × 15 = 300cm = 3m

Thus, the least pressure = Force/ Area

= 50N / 3m = 16.667N/m = 16.667 P


★★ HOPE THAT HELPS ☺️ ★★

Answer 2

area of block = 2(lb+bh+hl) = 0.06 m^2
pressure exerted = force/ area
=50/0.06
=833.33