Physics, asked by Anonymous, 10 months ago

A rectangular block weighing 192 N has the dimensions 8cm x 6cm x 2cm.
What is maximum and minimum pressure that it can exert when it is placed on a horizontal surface?

Answers

Answered by anantrajusharma
1

Answer:

Greater Pressure = 120,000Pa

Lesser Pressure = 40,000Pa

Explanation:

Greater Pressure = 120,000Pa

Lesser Pressure = 40,000Pa

We know that

P=F/A

Where...

P=Pressure (expressed in Pa for pascals. )

F= Force (expressed in N for newtons. )

A= Area (expressed in m² for metres squared. )

Our glass block has dimensions of 8cm×6cm×2cm

And so the two surface areas we can use are...

8×6 = 48cm²

8×2=16cm²

A is in m² so.....

1 m² = 10,000 cm ²

48/10,000 = 0.0048 m²

16/10,000 = 0.0016 m²

So now that we have our two surface areas, we can calculate our pressures.

Greater Pressure = 192/0.0016 = 120,000Pa

Lesser Pressure = 192/0.0048 = 40,000 Pa

JAI SHREE KRISHNA

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