Math, asked by IYashviI, 5 months ago

A Rectangular box of Length 40cm , Breadth 25cm , and Height 20cm is to be made of tin. What is the area of the Tin Sheet required if the box has a lid also ?​

Answers

Answered by ayush31129
3

Answer:

20000cm³ is the correct answer

Answered by thebrainlykapil
146

\large\underline{ \underline{ \sf \maltese{ \: Question:- }}}

  • A Rectangular box of Length 40cm , Breadth 25cm , and Height 20cm is to be made of tin. What is the area of the Tin Sheet required if the box has a lid also ?

 \\  \\

\large\underline{ \underline{ \sf \maltese{ \: Given:- }}}

  • Length of the Box = \red{  \boxed{40cm}}
  • Breadth of the Box = \red{  \boxed{25cm}}
  • Height of the Box = \red{  \boxed{20cm}}

 \\

\large\underline{ \underline{ \sf \maltese{ \: To \: Find:- }}}

  • Area of the Tin Sheet required if the box has a lid also .

 \\

\large\underline{ \underline{ \sf \maltese{ \: Solution:- }}}

\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\: Total \: Surface \: Area \: = \:2( \: lb \:  +  \: lh \:  +  \: bh \: )    }} }\\ \\\end{gathered}\end{gathered}\end{gathered}

\qquad \quad {:} \longrightarrow \sf{\sf{ 2(40 \times 25 \:  +  \: 40 \times 20 \:  +  \: 25 \:  \times  \: 20) }}\\

\qquad \quad {:} \longrightarrow \sf{\sf{ 2(1000 \:  +  \: 800 \:  +  \: 500) }}\\

\qquad \quad {:} \longrightarrow \sf{\sf{ 2\: \times \: 2300 }}\\

\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{ Total \: Surface \: Area \: = \: 4600\: {cm}^{2}   }}}\\

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\begin{gathered}\begin{gathered}\qquad \therefore\: \sf{ Area \: of \: Tin \: Sheet  \: = \underline {\underline{4600\: {cm}^{2}  }}}\\\end{gathered}\end{gathered}

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\underbrace\green{\underline{\boxed{ \sf \orange{More \: For \: Knowledge }}}}

★ Additional Information :

  • Volume of cylinder = πr²h
  • T.S.A of cylinder = 2πrh + 2πr²
  • Volume of cone = ⅓ πr²h
  • C.S.A of cone = πrl
  • T.S.A of cone = πrl + πr²
  • Volume of cuboid = l × b × h
  • C.S.A of cuboid = 2(l + b)h
  • T.S.A of cuboid = 2(lb + bh + lh)
  • C.S.A of cube = 4a²
  • T.S.A of cube = 6a²
  • Volume of cube = a³
  • Volume of sphere = 4/3πr³
  • Surface area of sphere = 4πr²
  • Volume of hemisphere = ⅔ πr³
  • C.S.A of hemisphere = 2πr²
  • T.S.A of hemisphere = 3πr²

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