Question

a rectangular cardboard is 1m60cm long and 1m30cm wideif bothare correct to the nearest meter then find the possible area of cardboard​

Answer 1

Answer:

it's answer is that

Step-by-step explanation:

Total length of tape required = Perimeter of rectangle

                                                     = 2(length + breadth)

                                                    = 2(40 + 10)

                                                    = 2 * 50

                                                    = 100 cm

                                                    = 1 m           {Since 1 m = 100 cm}

Thus, the total length of tape required is 100 cm or 1 m.

Question 3:

A table-top measures 2 m 25 cm by 1 m 50 cm. What is the perimeter of the table-top?

Answer:

Length of table top = 2 m 25 cm = 2 m + 0.25 cm = 2.25 m

Breadth of table top = 1 m 50 cm =  1m + 0.50 m = 1.50 m

Perimeter of table top = 2(length + breadth)

= 2(2.25 + 1.50)

= 2 * 3.75

= 7.50 m

Thus, the perimeter of table top is 7.5 m.

Question 4:

What is the length of the wooden strip required to frame a photograph of length and breadth 32 cm and 21 cm respectively?

Answer:

Length of wooden strip = Perimeter of photograph

Perimeter of photograph = 2(length + breadth)

 = 2(32 + 21)

 = 2 * 53 cm

= 106 cm

Thus, the length of the wooden strip required is equal to 106 cm.

Question 5:

A rectangular piece of land measures 0.7 km by 0.5 km. Each side is to be fenced with 4 rows of wires. What is the length of the wire needed?

Answer:

Since the 4 rows of wires are needed.

Therefore the total length of wires is equal to 4 times the perimeter of rectangle.

Perimeter of field = 2(length + breadth)

                                 = 2(0.7 + 0.5)

                                 = 2 * 1.2

                                 = 2.4 km

                                 = 2.4 * 1000 m

                                 = 2400 m

Thus, the length of wire = 4 * 2400 = 9600 m = 9.6 km

Question 6:

Find the perimeter of each of the following shapes:

(a) A triangle of sides 3 cm, 4 cm and 5 cm.

(b) An equilateral triangle of side 9 cm.

(c) An isosceles triangle with equal sides 8 cm each and third side 6 cm

Answer:

(a) Perimeter of triangle = Sum of all sides

                                            = 3 cm + 5 cm + 4 cm

                                            = 12 cm

(b) Perimeter of equilateral triangle = 3 * side

                                                                 = 3 * 9 cm

                                                                 = 27 cm

(c) Perimeter of isosceles triangle = Sum of all sides

                                                             = 8 cm + 6 cm + 8 cm

                                                             = 22 cm

Question 7:

Find the perimeter of a triangle with sides measuring 10 cm, 14 cm and 15 cm.

Answer:

Perimeter of triangle = Sum of all three sides

                                      = 10 cm + 14 cm + 15 cm = 39 cm