Question

a rectangular carpet has an area of 120 m square and it's perimeter is 46m. then find the length of its diagonal...​

Answer 1

Answer:

l=15m

or

8m

P Perimeter

46

m

A Area

120

m²

Using the formulas

A=wl

P=2(l+w)

There are 2 solutions forl

l=P

4+1

4P2﹣16A=46

4+1

4·462﹣16·120=15m

l=P

4﹣1

4P2﹣16A=46

4﹣1

4·462﹣16·120=8m

Answer 2

Answer:

17m

Step-by-step explanation:

perimeter of rectangle = 2(l+b)

Area of rectangle = l x b

Here , the rectangular carpet has perimeter of 46m

so, 2(l+b) =46

l+b=46/2

l+b=23

Here , the rectangular carpet has area of 120m^2

By Pythagoras theorem

(l)^2 + (b)^2 = (hypotenuse)^2 [here hypotenuse is diagonal )

(l+b)^2 - 2(lb) = (hypotenuse)^2

(23)^2-2(120) = (hypotenuse)^2

529-240 = (hypotenuse)^2

✓289 = (hypotenuse)

17 =(hypotenuse)

Therefore , the length diagonal is 17m