Math, asked by rajankit0651, 4 days ago

A rectangular carpet has an area of 220 yd2. The width w is 9 yards less that the length I. Find the perimeter p of the carpet.
(1)54 yds
(2)42 yds
(3) 26 yds
(4)62

Answers

Answered by aakhyapatel18jun2012

Answer:

P≈66.89 yd is your answer

Step-by-step explanation:

hole it's help you

Answered by Swarup1998

The perimeter of the carpet is p = 62 yards.

Let the length of the rectangular carpet is l yards.

Since the width w is 9 yards less than the length, then

w = l - 9

Then the area of the rectangular carpet

= length × width

= l × w

= l (l - 9) yard²

= (l² - 9l) yard²

According to the question,

l² - 9l = 220

⇒ l² - 9l - 220 = 0

⇒ l² - 20l + 11l - 220 = 0

⇒ l (l - 20) + 11 (l - 20) = 0

⇒ (l - 20) (l + 11) = 0

Since length cannot be negative, then l = 20 yards.

Thus width (w) = (20 - 9) yards = 11 yards

Thus the perimeter of the rectangular carpet

p = 2 (length + width)

= 2 (20 + 11) yards

= 2 × 31 yards

= 62 yards