Question

a rectangular city lot in bacoor has a perimeter of 540.The width of the lot is 150 m less than it's length.Find the width and length of the lot(Use P=2l+2w)​

Answer 1

Answer:

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Answer 2

Answer:

Length of the lot = 210 m

Width of the lot = 60 m

Step-by-step explanation:

Given:

• Perimeter of the lot = 540 m
• Width of the lot = 150 m less than the length

To Find:

• Width and length of the lot

Solution:

Here we have to find the length and width of the rectangular lot.

By given,

Width of the lot = Length - 150 m

b = l - 150 -----(1)

Perimeter of a rectangle is given by,

Perimeter of rectangle = 2 (l + b)

where l = length

          b = breadth

Substitute the data,

2 (l + b) = 540

Substitute the value of b from equation 1

2 ( l + l - 150) = 540

2l - 150 = 270

2l = 270 + 150

2l = 420

l = 420/2

l = 210 m

Hence length of the lot is 210 m.

Substitute the value of l in equation 1

b = 210 - 150

b = 60 m

Hence width of the lot is 60 m.

Verification:

Width = length -150

60 = 210 -150

60 = 60

Perimeter = 540

2(l + b) = 540

2 (60 + 210) = 540

2 × 270 = 540

540 = 540