A rectangular coil of 100 turns and area 200 cm² carrying 2A
current is place in a uniform magnetic field of 2 T. Calculate the maximum torque
on the coil.
Answers
Answer:
The answer of this question is 8Nm.
Explanation:
T= NIAB sinθ
N=100, A= 200cm^2 = 0.02m^2 , B=2T, I= 2A.
putting values:
T= 100 * 2 * 0.02 * 2 * sin (90)
T= 8 Nm
Answer:
the maximum torque on the rectangular coil is 4 Nm (Newton-meters) when it carries a current of 2 A and is placed in a uniform magnetic field of 2 T.
Explanation:
The maximum torque on a rectangular coil placed in a uniform magnetic field is given by the formula:
τ = NABBsinθ
where:
N is the number of turns in the coil
A is the area of each turn of the coil
B is the magnetic field strength
θ is the angle between the normal to the coil and the direction of the magnetic field
In this case, the rectangular coil has 100 turns, an area of 200 cm² (0.02 m²), and carries a current of 2 A. The magnetic field strength is 2 T.
The maximum torque will be produced when the normal to the coil is perpendicular to the direction of the magnetic field, i.e., θ = 90°.
Therefore, we can calculate the maximum torque on the coil as follows:
τ = NABBsinθ = (100)(0.02 m²)(2 T)(sin 90°) = 4 Nm
Therefore, the maximum torque on the rectangular coil is 4 Nm (Newton-meters) when it carries a current of 2 A and is placed in a uniform magnetic field of 2 T.