Question

A rectangular coil of 400 turns on frame of 3cm x 2cm is suspended in magnetic field of induction
0.1 T. A current of 10-? A flows through the coil. The torque on it in N-m is
[ ]
a) 2.4 x 10-6
b) 2.6 x 10-2
c) 2.4 x 10-9
d) 4.8 x 10-8​

Answer 1

im assuming that the current through coil is 10A aa the question you have mentioned is not clear.

still im attaching the pic for the ans!!

Answer 2

Explanation:

tau = NBIA = 400 ×0.1×10^-7×6×10^-4

= 2.4×10^-9 this is the answer