Question

a rectangular conducting cube (resistivity p) has dimension l×b×h.when current is passed through the length side,the resistance offered by the cube is______?
(a).
$\frac{pl}{bh}$
(b).
$\frac{pb}{hl}$
(c).
$\frac{ph}{lb}$
(d).
$p \times \frac{lb}{ {h}^{2} }$
pls give the correct explanation and answer...........if i am satisfied with your correct answer I will mark you as brainliest.......

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Answer 1

Gudnyt

How r u??❤️

Here's ur answer

We know that,

Resistance = R = ρl/A     (l is the length, A is the area)

When passing through the length,

Length = l

Area = bh

R = ρl/bh

Hope this is helpful to you

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