Question

a rectangular container of base 50 cm by 30 cm is filled with water to a depth of 5 cm how much is the pressure exerted at the base ( take density of water=1000 kg/m³ and g=10 m/s²)

Answer 1

Answer:

given

h = 5cm

=0.05m

d= 1000kg/M3

g=10m/S2

P= h.d.g.

= 0.05*1000*10

=500Nm

Answer 2

Given,

Density of water = 1000 kg/m3

Base of the rectangular water container = 50 cm by 30 cm  

Height of water container = 5 cm

Acceleration due to gravity  = 9.8 m/s²

To find,

The pressure exerted at the base of the water container

Solution,

We can simply solve this numerical problem by using the subsequent process  

Now,

Density of water (ρ) = 1000 kg/m3

Base of the rectangular container = 50 cm by 30 cm  

Height of water container (h)= 5 cm = 0.05m

Acceleration due to gravity (g) = 9.8 m/s²

Pressure (P) = ?

As we know that,  

P = ρgh

where,  

P = Pressure, g = Acceleration due to gravity, & h = Height

P = 1000 kg/m³ x 9.8 m/s² x 0.05m

P = 490N/m²

Hence, the pressure exerted at the base of the container is 490N/m²