Question

A rectangular container of milk is 35 cm long and 21 cm
wide. It contains 2.750 litres of milk. What is the depth of
the milk in the container?
olume and Surface Area​

Answer 1

${\huge{\rm{\underline{\underline{\maltese\;Correct\; Question:-}}}}}$

Q) A rectangular container of milk is 35 cm long and 21 cm wide . It contains 2.750 litres of milk . What is the depth of the milk in the container ?

${\huge{\rm{\underline{\underline{\maltese\;Answer\checkmark}}}}}$

$\frak{Given}\begin{cases}\sf{Length_{(Container)}=\bf{35cm}}\\ \sf{Breadth_{(Container)}=\bf{21cm}}\\ \sf{Volume{(Milk)}=\bf{2.750\: litres}}\end{cases}$

$\frak{To \;Find}\begin{cases}\rm{Depth\;of\;the\;Milk}\end{cases}$

${\underline{\textit{\textbf{★Solution:–}}}}$

→ Volume of Milk = 2.750 litres .

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \sf{1 \: litre = 1000 \: {cm}^{3}}}$

→ Volume of Milk = 2.750 × 1000 cm³

→ Volume of Milk = 2750 cm³

Let ,

the depth of the milk in the container be h (in cm)

We have ,

• Length = 35 cm
• Width/Breadth = 21 cm
• Depth = h cm

$\rm \: volume _{milk} = length \times width \times depth \:$

$\mapsto \rm \: \cancel{ 2750} \: \cancel{cm}^{3} = \cancel{ 35} \times 21 \times h \: \cancel{cm}^{3}$

$\mapsto \rm \: 550 = 7 \times 21 \times h$

$\mapsto \rm \: 550 = 147 \times h$

$\mapsto \: \: \: \: \: \: \: \: \: \: {\underline{ \boxed{ \frak{h}= \frac{550}{147}}}}$

So ,

Depth of the milk = ${\bold{\dfrac{550}{147}}}$ or 3.74 cm .

_________________________

★ Know More :–

• Volume of Cuboid = length×breadth×height .

• TSA of Cuboid = 2(lb+bh+lh) .

• CSA of Cuboid = 2(l+b)×h .

→ The unit of volume = unit³

→ The unit of Surface Area = unit²