A rectangular courtyard is 142m 80cm long and 31cm92m broad. It is to be paved with square stones of the same size. Find the least possible number of such stones
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A rectangular courtyard is 18m 72cm long and 13m 20cm broad
A rectangular courtyard is 18m 72cm long and 13m 20cm broad. It is to be paved with square tiles of the same size. Find the leat possiable no. of such till
Answer.
Given length of rectangular courtyard = 18 m 72 cm = 1872 cm
Width of rectangular courtyard = 13 m 20 cm = 1320 cm
To find the square tile of maximum side we take the HCG of 1872 and 1320 By Euclid’s division lemma
we have 1872 = 1320 × 1 + 552 1320 = 552 × 2 + 216 552 = 216 × 2 + 120 216 = 120
× 1 + 96 120 = 96 × 1 + 24 96 = 24 × 4 + 0 Hence the HCF is 24
Therefore maximum side of the square = 24 cm Number of tiles required = (Area of rectangular courtyard)
(Area of square tile) = (1872 × 1320)/(24 × 24) = 4290
Hence 4290 tiles are required.
A rectangular courtyard is 18m 72cm long and 13m 20cm broad
A rectangular courtyard is 18m 72cm long and 13m 20cm broad. It is to be paved with square tiles of the same size. Find the leat possiable no. of such till
Answer.
Given length of rectangular courtyard = 18 m 72 cm = 1872 cm
Width of rectangular courtyard = 13 m 20 cm = 1320 cm
To find the square tile of maximum side we take the HCG of 1872 and 1320 By Euclid’s division lemma
we have 1872 = 1320 × 1 + 552 1320 = 552 × 2 + 216 552 = 216 × 2 + 120 216 = 120
× 1 + 96 120 = 96 × 1 + 24 96 = 24 × 4 + 0 Hence the HCF is 24
Therefore maximum side of the square = 24 cm Number of tiles required = (Area of rectangular courtyard)
(Area of square tile) = (1872 × 1320)/(24 × 24) = 4290
Hence 4290 tiles are required.
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