A rectangular courtyard is 18m 72cm long and 13m 20cm broad it is to be paved with square tiles of wame size. Finf the least possible numberof such tiles
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A rectangular Courtyard is 18m 72cm long and 13m 20cm broad it is to be paved with square tiles of the same size
18m72cm = 1872cm and 13m20cm = 1320cm
now ,
let us find the hcf of 1872 cm and 1320 cm
=>[we can use Euclids division lemma method]
=>hcf will be 24
now ,
=>Number of tiles required = (Area of rectangular courtyard)/(Area of square tile)
= (1872 × 1320)/(24 × 24)
= 4290 [sq.cm tiles]
==================================
hope its helpz
18m72cm = 1872cm and 13m20cm = 1320cm
now ,
let us find the hcf of 1872 cm and 1320 cm
=>[we can use Euclids division lemma method]
=>hcf will be 24
now ,
=>Number of tiles required = (Area of rectangular courtyard)/(Area of square tile)
= (1872 × 1320)/(24 × 24)
= 4290 [sq.cm tiles]
==================================
hope its helpz
Answered by
1
Answer:
It is given that a rectangular hall is 18m 72cm long and 13m 20cm broad which means that rectangular hall is 1872 cm long and 1320 cm broad.
The given integers 1872 and 1320 can be factorised as follows:
1872=2×2×2×2×3×3×13
1320=2×2×2×3×5×11
We know that HCF is the highest common factor, therefore, the HCF of 1872 and 1320 is:
HCF=2×2×2×3=24
Therefore, maximum side of the square is 24 cm and
Since, area of rectangular courtyard is 1872×1320=2471040 and area of the square tile is 24×24=576.
Now, the number of tiles required is:
24×24
1872×1320
=
576
2471040
=4290
Hence, the least possible number of such tiles is 4290.
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