Question

A rectangular display board depicting “BE DISCIPLINED” is kept near the main gate of the school. Length of the board is 4m more than its breadth b. If the perimeter of the board is 84m , find the length and breadth of the rectangle.

Answer 1

Answer:

Let breadth be x

Then length is x+4

Perimeter of rectangle=2(l+b)

84meters=2(x+4+x)

84=4x+8

4x=76

x=19meters

Breadth is 19 meters

Length is 4 more than breadth

Length=x+4=19+4

Length=23 meters

Step-by-step explanation:

Rate, click thanks and mark as brainliest.

Read more on Brainly.in - https://brainly.in/question/20197286#readmore

Answer 2

Answer:

ᴛʜᴇ ʙʀᴇᴀᴅᴛʜ ᴏꜰ ᴛʜᴇ ʀᴇᴄᴛᴀɴɢʟᴇ ʙᴇ " x " ᴍᴇᴛʀᴇꜱ .

ᴛʜᴇɴ ʟᴇɴɢᴛʜ = ( x + 4 ) ᴍᴇᴛʀᴇꜱ

ᴘᴇʀɪᴍᴇᴛᴇʀ = 84

ᴀᴄᴄᴏʀᴅɪɴɢ ᴛᴏ Qᴜᴇꜱᴛɪᴏɴꜱ ,

2 ( x + x + 4 ) = 84

⇒ 2 ( 2x + 4 ) = 84

⇒ 2 ( 2x + 4 ) = 84

⇒ 4x = 84 - 8

⇒ 4x = 76

⇒ x = 76/4

⇒ x = 19

ʜᴇɴᴄᴇ , ʙʀᴇᴀᴅᴛʜ ᴏꜰ ʀᴇᴄᴛᴀɴɢʟᴇ = 19ᴍ ᴀɴᴅ

ʟᴇɴɢᴛʜ ᴏꜰ ʀᴇᴄᴛᴀɴɢʟᴇ = 19 + 4 = 23ᴍ