Question

A rectangular feild is 15 m long and 10 m wide. Another rectangular feild having the same perimeter has its side in the ratio 4:1. Find the dimension of the rectangular feild.​

Answer 1

Answer:

Perimeter of 1st rectangle= 2(15+10)

= 2* 25

= 50 m

given, 2nd rectangle perimeter = 50 m

let the length of the 2nd rectangle be 4x and breadth be 1x or x

ATQ,

=2(4x+x) = 50

=> 2*5x = 50

=> 5x = 50/2

=> x = 25/5

=> x = 5

therefore , the dimensions of the rectangle are : length = 4x or 4*5 = 20 m

= x or 5m