a rectangular feild isof dimension 20m×15m.two paths run parallel to the sides of the rectangle through the centere of the feild the width of the longer path is 2m and that shorter path is 1m find i) the area of the paths ii) area of the remaining portion of the feild iii) the cost of constructing the roads at the rate of #10 per sq.m.
Answers
Answer:
Step-by-step explanation:
The area of the paths is 53 m²
The area of the remaining portion of the field is 247 m².
The cost of constructing the roads at the rate of 10 per sq.m is Rs. 530.
Step-by-step explanation:
Dimensions of rectangular field is 20 m x 15 m
The width of the longer path is 2 m and that of the shorter path is 1 m
Step 1:
The area of the rectangle ABCD = length * breadth = 20 * 15 = 300 m²
Area of the shorter path IJKL = 15 * 1 = 15 m²
Area of the londer path EFGH = 20 * 2 = 40 m^2
and,
Area of the middle common path MNOP = 2 * 1 = 2 m²
∴ Area of the paths is given by,
= [Area of the shorter path IJKL] + [Area of the londer path EFGH] - [Area of the middle common path MNOP]
= 15 + 40 - 2
= 53 m²
∴ Area of the remaining protion is given by,
= [The area of the rectangle ABCD] - [Area of the paths]
= 300 - 53
= 247 m²
The rate of constructing the roads is given as Rs. 10 per sq. meter
∴ The total cost of constructing the roads is given by,
= 53 m² * Rs. 10
= Rs. 530