Question

a rectangular field 750m long and 450 broad has 2 roads in the middle of it which are 5m wide running at right angle to each other .one is along the length and other along the breadth .Find the area of the road

Answer 1

Given: Length of a rectangular field = 750m ,

Breadth of a rectangular field = 450m.

Now, if the road = 5m is wide and running at the right angles to each other, then

the area of the path running along the breadth = 450×5=2250^m² and

the area of the path running along the length = 750×5=3750^m²

∴Area of path= the area of path along the breadth +area of path along length -crossing area over estimation.

Answer 2

So now imagine your rectangular field of 750 x 450 dimensions
Area of rectangle is $length * breadth$
So area of first road is $5 * 750 = 3750$
Area of second road is $5 * 450 = 2250$
But wait they intersect at centre which is centre
Area of square of side is $side * side$
Which is $5 * 5 = 25$
So total area covered by road is 
Area of first road + Area of second road - area of intersection
$3750 + 2250 - 25 = 5975$