Question

a rectangular field has 80m length and 48m breadth. Three roads, each of width 2m pass through the field such that two roads are parallel to the breadth and the third road parallel to the length. Find the area covered by the three roads.​

Answer 1

Step-by-step explanation:

80×48=3840m^2= area of rectangular field area of 1 road parallel to breadth=2×48=96 area of 2 roads parallel to breadth=96×2=192 area of 1 road parallel to length = 2×80=160 area of 1 repeated square= 2×2=4 area of 2 repeated square =4×2=8 area of roads = (160+192)-8=344

PLEASE MARK THE BRAINLIEST

Answer 2

$\bf{\Huge{\underline{\boxed{\bf{\green{ANSWER\::}}}}}}$

$\bf{\Large{\underline{\bf{Given\::}}}}}$

A rectangular field has 80m length and 48m breadth. Three roads, each of width 2m pass through the field such that two roads are parallel to the breadth and the third road parallel to the length.

$\bf{\Large{\underline{\bf{To\:find\::}}}}}$

The area covered by the three roads.

$\bf{\Large{\underline{\boxed{\bf{\blue{Explanation\::}}}}}}$

$\bf{We\:have\begin{cases}\sf{A\:rectangular\:field\:of\:length=80m}\\ \sf{A\:rectangular\:field\:of\:breadth=48m}\end{cases}}$

→ Area of rectangular field = (Length × Breadth)   [sq.unit]

→ Area of rectangular field = (80 × 48)m²

→ Area of rectangular field = 3840m²

A/q

Each three roads width of 2m.

→ The length of rectangular field is 80m of parallel road its width 2m;

∴The area covered of road = (80 × 2)m² = 160m²

→ The breadth of rectangular field is 48m of parallel road its width 2m;

∴The area covered of road = (48 × 2)m² = 96m²

In rectangular field the area of two such road;

⇒ Area = (2 × 96)m²

⇒ Area = 192m²

Now,

→ The intersection of two road is a square of side 2m;

∴ The area of two such square:

⇒ 2 × (2)²

⇒ (2 × 4)m²

⇒ 8m²

Hence,

The area covered by the three roads is;

→ (160 + 192)m² - 8m²

→ 352m² - 8m²

→ 344m²