A rectangular field has 80m length and 48m breadth.Three roads each of width 2m pass through the field such that two roads are parallel to the breadth and the third road parallel to the length.Find the area covered by three roads.
Answers
Answer:
344 meter²
Step-by-step explanation:
We know that width of each road is 2 m.
Length of two of the roads (parallel to the breadth) = breadth = 48 m.
Length of one road (parallel to the length) = length = 80 m.
i] Area of two roads parallel to the breadth = 2(width * breadth)
= 2( 2*48)
= 2(96)
= 192 m²
ii] Area of road parallel to the length = width of road * length
= 2 * 80
= 160 m²
Now, subtract the areas common in both the roads :
the length and breadth of these common areas is 2 m.
Areas of the common part = (2*2) + (2*2)
= 4 + 4
= 8 m²
Upon subtracting these from the total area of the roads :
(192 + 160) - 8
344 m²
The area covered by the three roads is 344 m. square
A rectangular field has 80m length and 48m breadth. Three roads, each of width 2m pass through the field such that two roads are parallel to the breadth and the third road parallel to the length.
The area covered by the three roads.
→ Area of rectangular field = (Length × Breadth) [sq.unit]
→ Area of rectangular field = (80 × 48)m²
→ Area of rectangular field = 3840m²
A/q
Each three roads width of 2m.
→ The length of rectangular field is 80m of parallel road its width 2m;
∴The area covered of road = (80 × 2)m² = 160m²
→ The breadth of rectangular field is 48m of parallel road its width 2m;
∴The area covered of road = (48 × 2)m² = 96m²
In rectangular field the area of two such road;
⇒ Area = (2 × 96)m²
⇒ Area = 192m²
Now,
→ The intersection of two road is a square of side 2m;
∴ The area of two such square:
⇒ 2 × (2)²
⇒ (2 × 4)m²
⇒ 8m²
Hence,
The area covered by the three roads is;
→ (160 + 192)m² - 8m²
→ 352m² - 8m²
→ 344m²