Question

a rectangular field has a length 18 and 48 breadth three rods each of width 2 metre pass through the field such that two roads are parallel to the breadth and third road parallel to the length find the area covered by the three roads​

Answer 1

Answer:

Length of two roads are 48 m each  and width=2 m

     Area of these two roads= 2*48*2= 192 m²

Length of one road is 80 m    

  Area of this road = 80*2=160 m²     

 Common area of these roads= 2*2*2= 8 m²

Area covered by three roads =192 + 160 - 8 = 344 m²

The area covered by three roads= 344m²

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Answer 2

Step-by-step explanation:

ans is 344m^2

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