Question

A rectangular field has a perimeter 92m & its
length is 25m. Find the area of the field?

(A. 640 m²
(B. 20 m² (C. 525 m² 1 (D. 65 m²


You know answer ...​

Answer 1

Answer:

◽275m

Step-by-step explanation:

let the breadth be b

perimeter of field=92m

2(l+b) =92m

2(25+b). =92m

25+b. =92/2

b. = 46-25

◽. =21m

hence, breadth is 21m

area of field = (lxb)

= (25x21)

=525m^2

hope become helpful

Answer 2

Question :

A rectangular field has a perimeter 92m and its

length is 25m. Find the area of the field.

(A) 640 m²

(B) 20 m²

(C) 525 m²

(D) 65 m²

Solution :

Given :-

• perimeter of rectangular field = 92m

• Length = 25m

To find :

• the area of the field

Formula used :

• Perimeter of rectangle = 2( length+breadth)

• Area of rectangle = length × breadth

Procedure :

we know that :-

Perimeter of rectangle = 2( length+breadth)

It is given that perimeter of rectangular field is 92m and Length is 25m.

Therefore now we will find breadth :-

⟹ 92= 2 ( 25+b) ..... ( b = breadth)

⟹ 92/2 = 25+ b

⟹ 92/2 = 25+ b

⟹ 46= 25+ b

or

⟹ 25+ b = 46

⟹ b = 46-25

⟹ b = 21 m

breadth = 21m

Now to find out area of rectangular field use the given formula:-

⟹ Area of rectangle = length × breadth

⟹ Area of rectangle = 25 × 21

⟹ Area of rectangle = 525 m²

Answer :

Option ( C) 525 m² is correct answer.

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$\large\bf\pink{Additional-Information}$

• Area of circle = 2πr

• Area of square = (side)²

• area of Rhombus = 1/2(diagonal 1)(diagonal 2)

• T.S.A of cylinder = 2πrh + 2πr²

• C.S.A of cone = πrl

• T.S.A of cone = πrl + πr²

• C.S.A of cuboid = 2(l + b)h

• T.S.A of cuboid = 2(lb + bh + lh)

• C.S.A of cube = 4a²

• T.S.A of cube = 6a²

• Surface area of sphere = 4πr²

• C.S.A of hemisphere = 2πr²

• T.S.A of hemisphere = 3πr²

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