a rectangular field has a t m length and 48 M breadth three rods each of width to pass through the field such that two roads are parallel to the breadth and third Road parallel to the length find the area covered by the three roads
Answers
Answer:
Step-by-step explanation:
We know that width of each road is 2m.
Length of two of the roads (parallel to the breadth) = breadth = 48m.
Length of one road (parallel to the length) = length = 80m.
i] Area of two roads parallel to the breadth = 2(width * breadth)
= 2( 2*48)
= 2(96)
= 192 m. square
ii] Area of road parallel to the length = width of road * length
= 2 * 80
= 160 m. square
Now, subtract the areas common in both the roads :
We can see that the length and breadth of these common areas is 2 m.
Areas of the common part = (2*2) + (2*2)
= 4 + 4
= 8 m. square
Upon subtracting these from the total area of the roads :
(192 + 160) - 8
344 m. square
The area covered by the three roads is 344 m. square.