a rectangular field has an area 28800m.sq. its length is twice as long as its width. what is the length of its sides?
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Answered by
15
let breadth of the rectangular field be x metre.
then length be 2x metre.
now,area of rectangle =length×breadth
so,ATQ
2x×x=28800.
2x^2=28800.
x^2=28800/2
x^2=14400.
x=root under 14400
x=120
therefore breadth of the field =120m.
and length of the field =120×2=240m.
then length be 2x metre.
now,area of rectangle =length×breadth
so,ATQ
2x×x=28800.
2x^2=28800.
x^2=28800/2
x^2=14400.
x=root under 14400
x=120
therefore breadth of the field =120m.
and length of the field =120×2=240m.
areebaafzal286:
then?
Answered by
5
Hey Friend !
Breadth = b
Length = 2b
Area of a rectangle = length x breadth
= 2b x b
= 2b²
2b² = 28800m²
b² = 28800 /2
b² = 14400
b = √ 14400
b = 120 m
Length = 2b = 2× 120 = 240 m
Breadth = b
Length = 2b
Area of a rectangle = length x breadth
= 2b x b
= 2b²
2b² = 28800m²
b² = 28800 /2
b² = 14400
b = √ 14400
b = 120 m
Length = 2b = 2× 120 = 240 m
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