A rectangular field has an area of 1,764 m2. The width of the field is 13 m more than the length. What is the perimeter of the field? 121 m 144 m 168 m 170 m
Answers
Answered by
29
Given..
width is 13m more than length..
Let Length be X..the width will be x+13
we know that...
Area of a rectangle= L ×B
Given Area = 1764m^2.
substituting..
x(x+13) = 1764
x^2 +13x - 1764 =0
x^2 + 49x - 36x - 1764=0
x(x+49) - 36(x+49) =0
(x-36)(x+49) = 0
x = 36 or -49.. ignoring negative value..coz length wont be negative..
so length = x= 36
width= x+13 = 36+13 = 49
Perimeter of a rectangle= 2(L + B)
=2(36 + 49)
=2(85)
=170sqm
So option 'C' is the answer...
width is 13m more than length..
Let Length be X..the width will be x+13
we know that...
Area of a rectangle= L ×B
Given Area = 1764m^2.
substituting..
x(x+13) = 1764
x^2 +13x - 1764 =0
x^2 + 49x - 36x - 1764=0
x(x+49) - 36(x+49) =0
(x-36)(x+49) = 0
x = 36 or -49.. ignoring negative value..coz length wont be negative..
so length = x= 36
width= x+13 = 36+13 = 49
Perimeter of a rectangle= 2(L + B)
=2(36 + 49)
=2(85)
=170sqm
So option 'C' is the answer...
Answered by
31
Answer:
D 170 m
Step-by-step explanation:
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