Question

A rectangular field has an area of 3sq
units the length is one more than twice
and breadth x. frame an equation.
to represent this​

Answer 1

Answer:

2x^2 + x - 3 = 0.

Step-by-step explanation:

From the properties of quadrilaterals :

      Area of rectangle = length x breadth

Here,

      Area of rectangle is 3 unit^2 and breadth is x and length is one more than twice the breadth.

     So, length is 1 + twice of x ⇒ length is 2x + 1.

⇒ Area = 3

⇒ length x breadth = 3

⇒ ( 2x + 1 )x =3

⇒ 2x^2 + x = 3

⇒ 2x^2 + x - 3 = 0

      Hence the equation representing the situation is 2x^2 + x - 3 = 0.

Answer 2

Let the Length and Breadth of the rectangle be x and y respectively.

Given

$\bold{Breadth} = x\\\bold{Length} = 2x+1\\\bold{Area \ of \ the \ rectangular \ field} = 3 \ sq. \ units$

Area of the rectangle = Length * Breadth

$\implies (2x+1)(x) = 3\\\implies 2x^{2} +x=3\\\implies 2x^{2} +x-3=0$

$\boxed{\boxed{\bold{Therefore, \ the \ required \ equation \ is \ 2x^{2} +x-3=0}}}}$