Question

. A rectangular field has length 50m and width 40m. A path of equal width is constructed

inside periphery. If area of this path is 800 sq.mt. then find the width of the path​

Answer 1

Answer:

10

Step-by-step explanation:

toata area=50*40=2000m^2

area of path=800m^2

balance area=2000-800=1200

let width of the path=X

(50-x)(40-x)=1200

2000x-50x-40x+x^2=1200

x^2-90x+800=0

x^-80x-10x+800=0

X(x-80)-10(x-80)=0

(x-80)(x-10)=0

X=80or10

80is not possible

width of path=10