Math, asked by husain56, 10 months ago

A rectangular field is 100 m long and 80 m wide. A path 10 m wide path is to be
m wide. A path 10 m wide path is to be built inside the field all
along its border. Find the area of the path.
um long and 100 m wide rectangular park. A 20 m wide path is built surrounding
the garden along the boundary of the park. Find the area of the garden.
3. A square lawn is surrounded by a 5 m wide path. If the area of the path is 400 m-, find the area of the law.
4. A room is 20 m long and 15 m broad. It has to be carpeted after leaving a margin of 2 m all around it. Find
the area of the carpet required and the cost of carpeting it at 800 per m.
5. A piece of cloth is 5 m long and 2 m wide. A border of width 50 cm has to to printed and stitched all around
it on the outside. Find the cost of printing the border at 200 per m².
6. A rectangular lawn 100 m long and 70 m broad has two crossroads running in the middle of it—one 2 m
wide running parallel to its length and the other 5 m wide running parallel to its breadth. Find the area of
the lawn not covered by the crossroads.
7. A piece of cloth is 70 cm long and 50 cm wide, A strip of width 10 cm is cut from all around it. Find the
area of the remaining cloth and the area of the strip..
8 A mirror of length 30 cm and width 20 cm is to beframed with a 2 cm wide frame. Find the area of the
frame required. Also find the cost of framing at the rate of 20 per cm².​

Answers

Answered by qwsuccess
49

1) The area of the path is 3200 sq m.

  • length of field = 100m
  • breadth of field = 80 m
  • area of field = 8000 sq m
  • length of inside field = 100-10-10m = 80m
  • breadth of field = 80-10-10m = 60m
  • area of field = 4800 sq m
  • area of path = 8000 - 4800 sq m = 3200 sq m.

2) There is a garden inside a 150 m long and 100 m wide rectangular park. A 20 m wide path is built surrounding  the garden along the boundary of the park. Find the area of the garden.​

The area of the garden is 3200 sq m.

  • length of park = 150m
  • breadth of park = 100 m
  • area of park = 15000 sq m
  • length of inside garden = 150-20-20m = 110m
  • breadth of inside garden = 100-20-20m = 60m
  • area of inside garden = 6600 sq m

3) the area of the lawn is 225 sq m

Let the length of the lawn be x metres

then the length of the boundary is (x + 5 + 5) metre = (x+10) metre

  • Area of lawn = x^2 sq m
  • area of lawn with path = (x+10)^2 sq m
  • area of path = 400 sq m  

        ⇒  (x+5)^2 - x^2 sq m = 400  

        ⇒  x^2 + 20x + 100 - x^2 = 400  

        ⇒ 20x + 100 = 400

        ⇒ x = 15m

  • Area of lawn = 15*15 sq m = 225 sq m.

4) the area of the carpet is 176 sq m and the cost is Rs 1,40,800

  • length of room = 20m
  • breadth of room = 15m
  • length of carpet = 20-2-2m = 16m
  • breadth of carpet = 15-2-2m = 11m
  • area of carpet = 176 sq m
  • cost of carpeting = Rs 176 * 800 = Rs 1,40,800

5) the cost is Rs 1600

  • length of cloth = 5m
  • breadth of cloth = 2 m
  • area of cloth = 10 sq m
  • length of  cloth with border= 5+0.5+0.5m = 6m
  • breadth of cloth with border= 2+0.5+0.5m = 3m
  • area of cloth with border = 18 sq m
  • area of border = 18-10 sq m = 8 sq m.
  • cost = 8*200 rs = 1600rs.
Answered by krrew
15

Answer:

Step-by-step explanation:

1) The area of the path is 3200 sq m.

length of field = 100m

breadth of field = 80 m

area of field = 8000 sq m

length of inside field = 100-10-10m = 80m

breadth of field = 80-10-10m = 60m

area of field = 4800 sq m

area of path = 8000 - 4800 sq m = 3200 sq m.

2) There is a garden inside a 150 m long and 100 m wide rectangular park. A 20 m wide path is built surrounding  the garden along the boundary of the park. Find the area of the garden.​

The area of the garden is 3200 sq m.

length of park = 150m

breadth of park = 100 m

area of park = 15000 sq m

length of inside garden = 150-20-20m = 110m

breadth of inside garden = 100-20-20m = 60m

area of inside garden = 6600 sq m

3) the area of the lawn is 225 sq m

Let the length of the lawn be x metres

then the length of the boundary is (x + 5 + 5) metre = (x+10) metre

Area of lawn = x^2 sq m

area of lawn with path = (x+10)^2 sq m

area of path = 400 sq m  

       ⇒  (x+5)^2 - x^2 sq m = 400  

       ⇒  x^2 + 20x + 100 - x^2 = 400  

       ⇒ 20x + 100 = 400

       ⇒ x = 15m

Area of lawn = 15*15 sq m = 225 sq m.

4) the area of the carpet is 176 sq m and the cost is Rs 1,40,800

length of room = 20m

breadth of room = 15m

length of carpet = 20-2-2m = 16m

breadth of carpet = 15-2-2m = 11m

area of carpet = 176 sq m

cost of carpeting = Rs 176 * 800 = Rs 1,40,800

5) the cost is Rs 1600

length of cloth = 5m

breadth of cloth = 2 m

area of cloth = 10 sq m

length of  cloth with border= 5+0.5+0.5m = 6m

breadth of cloth with border= 2+0.5+0.5m = 3m

area of cloth with border = 18 sq m

area of border = 18-10 sq m = 8 sq m.

cost = 8*200 rs = 1600rs.

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