Question

A rectangular field is 15 2/3 m long and 12 4/5 m wide.Find its perimeter

Answer 1

length = 33/2
breath =64/5
perimeter of rectangle = 2(l+ b )
= 2(65+128/10 )
= 2×193/10
= 386/10

Answer 2

Concept:

Perimeter is the total length of the dimension of an object. Every object has dimensions so, every object is bound to have a perimeter.

Given:

The length of the field,

$15 \times \frac{2}{3} = \frac{47}{3} m$

The breadth of the field,

$12 \times \frac{4}{5} = \frac{64}{5}m$

Find:

Find the perimeter of the rectangular field.

Solution:

Applying the formula of the perimeter of a rectangle,

$peimeter = 2(l + b)$

therefore we get,

$p = 2( \frac{47}{3} + \frac{64}{5} ) \\ p = 2( \frac{235 + 192}{15} ) \\ p = 2 \times \frac{427}{15} \\ p = \frac{854}{15} \\ p = 56.93m$

Hence, the perimeter of the rectangular field is

$56.93m$

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