a rectangular field is 15m long and 10 m wide . Another rectangular field having the same perimeter has its sides in the ratio 4:1.Find the dimension of the rectangular field.
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hii friend here's your answer :-
Perimeter of 1st rectangle= 2(15+10)
= 2* 25
= 50 m
given, 2nd rectangle perimeter = 50 m
let the length of the 2nd rectangle be 4x and breadth be 1x or x
ATQ,
=2(4x+x) = 50
=> 2*5x = 50
=> 5x = 50/2
=> x = 25/5
=> x = 5
therefore , the dimensions of the rectangle are : length = 4x or 4*5 = 20 m
= x or 5m
HOPE IT HELPS U
Perimeter of 1st rectangle= 2(15+10)
= 2* 25
= 50 m
given, 2nd rectangle perimeter = 50 m
let the length of the 2nd rectangle be 4x and breadth be 1x or x
ATQ,
=2(4x+x) = 50
=> 2*5x = 50
=> 5x = 50/2
=> x = 25/5
=> x = 5
therefore , the dimensions of the rectangle are : length = 4x or 4*5 = 20 m
= x or 5m
HOPE IT HELPS U
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