A rectangular field is 16 m long and 10 m wide. There is a path of uniform width all
around it having an area of 120 m². Form the quadratic equation.
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Answer:
x = 2
Step-by-step explanation:
PQRS= rectangular field
ABCD= outer rectangle
1 : Length of rectangle PQRS = l = PQ= 16m
Breadth = b = QR= 10m
Width = xm
Length of rectangle ABCD = I' = AB= 16 +2x
breadth = b' = CD= 10+ 2x
2 : Length of rectangular field PQRS= l = 16
Breadth = b = 10
Area of rectangle PQRS = l x b = 160
Area of rectangle ABCD= l' x b' = (16+2x) (10+2x) = 4x² +52x + 160
3 : area of path = area of PQRS = area of ABCD
= 4x² +52x + 160 - 160
= 4x²+ 52x
4 : Area of path = 120
so, 120 = 4x²+ 52x
∴ x= 2 and ∴ x= -15
-15 will be rejected as length cannot be negative.
Therefore, x = 2
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