a rectangular field is 16 m long and 10 M wide there is a path of uniform width all round it having an area of 120 m square find the width of the path
RJRishabh:
is the answer coming in decimal
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PQRS= rect fieldABCD= outer rect
1: length of PQRS= l = PQ= 16mBreadth = b= QR= 10mwidth = xmlength of ABCD = I' = AB= 16 +2xbreadth= b' = CD= 10+ 2x
2: length of rect field PQRS= l= 16breadth = b = 10Area of PQRS= l x b = 160Area of ABCD= l' x b' = (16+2x)(10+2x)= 4x² +52x + 160
3: area of path = area of PQRS = area of ABCD = 4x² +52x + 160 - 160 = 4x²+ 52x
4: Area of path = 120so, 120 = 4x²+ 52xx= 2 and x= -15 -15 will be neglected so x=2
1: length of PQRS= l = PQ= 16mBreadth = b= QR= 10mwidth = xmlength of ABCD = I' = AB= 16 +2xbreadth= b' = CD= 10+ 2x
2: length of rect field PQRS= l= 16breadth = b = 10Area of PQRS= l x b = 160Area of ABCD= l' x b' = (16+2x)(10+2x)= 4x² +52x + 160
3: area of path = area of PQRS = area of ABCD = 4x² +52x + 160 - 160 = 4x²+ 52x
4: Area of path = 120so, 120 = 4x²+ 52xx= 2 and x= -15 -15 will be neglected so x=2
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