Question

A rectangular field is 16m long and 10m wide there is a path of uniform width all around it .i) taking the width of path x m find the dimensions of the outer rectangle .ii)express the area of the outer rectangle in terms of x m and also find area of the rectangular field . iii)express the area of the path in terms of x iv)find the width of the path if its area is 120m2

Answer 1

PQRS= rect field
ABCD= outer rect 

1: length of PQRS= l = PQ= 16m
Breadth = b= QR= 10m
width = xm
length of ABCD = I' = AB= 16 +2x
breadth= b' = CD= 10+ 2x

2: length of rect field PQRS= l= 16
breadth = b = 10
Area of PQRS= l x b = 160
Area of ABCD= l' x b' = (16+2x)(10+2x)= 4x² +52x + 160

3: area of path = area of PQRS = area of ABCD 
= 4x² +52x + 160 - 160 
= 4x²+ 52x

4: Area of path = 120
so, 120 = 4x²+ 52x
x= 2 and x= -15 
-15 will be neglected so x=2

Answer 2

Answer:

hwre is ur correct answer