Question

A rectangular field is 16m longer than its width . The perimeter is 208 m. What is the area of the field

Answer 1

$\textbf {Hey there, here is the solution.}$

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Perimeter = 208 m (given)

Define x:

Let the breadth be x

The length = x + 16

.

Solve x:

Perimeter = 2 (Length + Breadth)

208 = 2(x + 16 + x)

208 = 2(2x + 16)

208 = 4x + 32

4x = 176

x = 44 m

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Find the length and breadth:

Breadth = x = 44 m

Length = x + 16 = 44 + 16 = 60 m

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Find the area;

Area = Length x Breadth

Area = 44 x 60 = 2640 m²

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Answer: The area is 2640 m²

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⭐$\textbf {Cheers @ Simmisai}$⭐

Answer 2

L= w+16

2L+2W= 208

L+W= 104

A=LW

use substitution method

w+16+w = 104

2w+16=104

2w=104-16

2w= 88

w=44

l=44+16 = 60

A= 44 x 60

A=2640 m^2