A rectangular field is 16whole 1/2
m long and 12whole2/5m wide . Find the perimeter of the field
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Answered by
0
Answer:
maths
Step-by-step explanation:
l=16 1/2
b=12 2/5
p=2(l+b)
p=2(33/2+62/5)
p=2(165+124/10)
p=2(289/10)
p=57.8 is the answer
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Answered by
0
Answer:
Step-by-step explanation:
Given that,
Length of the field is 16 1/2
Width of the field is 12 2/5
Perimeter=2(l+b)
= 2(33/2+62/5)
= 2[{(5 x 33)+(2 x 62)}/10]
= 2([165+124]/10] (Here 2 gets cancelled with 10)
= 289/5
= 57.5
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