Math, asked by hemanandyini2208, 9 months ago

A rectangular field is 24m long and 15 m wide.how many triangular flower beds each of base 3m and height 4 m can be laid in this field

Answers

Answered by BrainIyMSDhoni
111

Answer:

60 triangular beds can be laid in this field.

Step-by-step explanation:

Given:-

Dimensions of the rectangular field are :

Lenght of the rectangular field = 24m

Breath of the rectangular field = 15m

As the area of the rectangle is

=> length x breath

So the area of rectangular field

=> 15 x 24 = 360m².

Now in each given triangle,

Height = 4m

Base = 3m

So-:

 =  > Area \: of \: triangle  =  \frac{1}{2} \times base \times height \\  =  > Area \: of \: triangle =  \frac{1}{2}  \times 3 \times 4 \\  =  > Area \: of \: triangle =  \frac{1}{ \cancel2}  \times 3 \times \cancel4 \\  =  > Area \: of \: triangle = 6 {m}^{2}

Number of Triangular flower beds which can be laid in the rectangular field

= [Total area of the rectangular field /Area of each triangular bed]

=> 360/6

=> 60

Therefore-:

There will be 60 triangular flower beds.

Answered by Anonymous
159

AnswEr :

we will calculate Area of Field First :

\bold{Rectangular \: Field} \begin{cases} \sf{Length=24 m} \\ \sf{Breadth=15 m}  \end{cases}

⇒ Area = Length × Breadth

⇒ Area = 24 m × 15 m

Area = 360 m²

we will calculate Ar. of Flower Bed Now :

\bold{Triangular \: Flower\:Bed} \begin{cases} \sf{Height=3 m} \\ \sf{Base=3 m} \end{cases}

\sf Area = \dfrac{1}{2}\times Height \times Base

\sf Area =\dfrac{1}{\cancel2}\times\cancel{4}\times3

\sf Area = 2 \times 3

\sf Area = 6 m^{2}

_________________________________

➟ Number = Ar. of Field / Ar. of Flower Bed

➟ Number = \sf \cancel\dfrac{360\:m^{2}}{6\:m^{2}}

Number = 60

60 Flower Beds can laid in that field.

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