Math, asked by parisinha331, 6 months ago

a rectangular field is 35 m long and 18 m wide, how many triangular flower beads of each base 7 m altitude 6m can be laid in this feild

Answers

Answered by ritiktiwari63
2

Answer:

area of rectangular region = length * breadth

(35*18) = 630

let n no. of triangular flower beads can be laid in this field having dimensions 6m height and base 7m

therefore, according to question

area of rectangular region = n x (area of triangular beads)

630 = n x(1/2 x base x height)

630 = n x(1/2x 7 x 6)

630 = n x 21

n = 630÷ 21

n= 30 ans

Answered by BrainlyPhantom
7

Given,

A rectangular field is 35 m long and 18 m wide.

To Find,

How many triangular flower beads of each base 7 m altitude 6m can be laid in this field.

Solution,

Let's find the area of each figures, one by one.

The Rectangular Field

Length = 35 m

Breadth = 18 m

Area = length x breadth

= 35 x 18

= 630 m²

The area of the rectangular field is 630 m².

The Triangular Flowerbed

Base = 7 m

Altitude (Height) = 6 m

Area =\mathtt{\dfrac{1}{2}\times\:base\times\:height}

= \dfrac{1}{2}\times7\times6

= 21 m²

The area of one right angled triangular flowerbed is 21 m².

→ Number of flowerbeds required

= \mathtt{\dfrac{Total\:area\:of\:field}{Area\:of\:one\:flowerbed}}

=\dfrac{630}{21}

= 30

∴ 30 triangular flowerbeds of area 21 m² each can be laid in the rectangular field of area 630 m².

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