Question

A rectangular field is 450m length and 250m broad. Find the coast of putting a fence around it a rate of 50 paise per meter​

Answer 1

Given :

• Length and Breadth of a Rectangular field is 450m and 250m.

To Find :

• Cost of putting a fence around it at rate of 50 paisa per metre.

Solution :

Firstly we will find Perimeter of Rectanglular Field :

$\longmapsto\tt{Length=450m}$

$\longmapsto\tt{Breadth=250m}$

Using Formula :

$\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}$

Putting Values :

$\longmapsto\tt{2(450+250)}$

$\longmapsto\tt{2(700)}$

$\longmapsto\tt\bf{1400cm}$

So , Perimeter of Field is 1400cm..

Now ,

Cost of Putting a fence around it at 50 p per metre :

$\longmapsto\tt{\dfrac{14{\cancel{00}}\times{50}}{1{\cancel{00}}}}$

$\longmapsto\tt{14\times{50}}$

$\longmapsto\tt\bf{Rs.700}$

So , Cost of fencing the field at the Rate of 50 p is Rs.700.

Answer 2

$\rule{380}2$

$\rm\boxed\checkmark$$\textsf{\textbf{\pink{Given :-}}}$

• A rectangular field is 450m length and 250m broad.

$\rm\boxed\checkmark$$\textsf{\textbf{\pink{To Find :-}}}$

• The cost of putting a fence around it a rate of 50 paise per meter.

$\rm\boxed\checkmark$$\textsf{\textbf{\pink{Solution :-}}}$

• Perimeter of rectangular field

$\implies{\textsf{\textbf{Lenght = 450m.}}}$

$\implies{\textsf{\textbf{Breadth = 250m.}}}$

• Formula

$\implies{\textsf{\textbf{Perimeter = 2(L + B)}}}$

• Value

$\implies{\textsf{2 × (450 + 250)}}$

$\implies{\textsf{2 × 700}}$

$\implies{\textsf{\textbf{1400m.}}}$

Perimeter = 1400m.

Now,

• Putting one fence around field = 50p.

$\implies$ 1400 × 50/100

$\implies{\textsf{14 × 50}}$

$\implies{\textsf{\textbf{₹700}}}$

$\rm\boxed\checkmark$ Cost of fencing field = ₹700.

$\rule{380}2$